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Empirical & Molecular Formula

An inorganic ...

Question

An inorganic compound contains 5.88% of hydrogen and 94.11% oxygen. The empirical formula of the compound is:

A

H O

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B

H_{2} O_{2}

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C

H_{2} O

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D

Both A and B

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Solution

The correct option is A $H O$
Ratio of atoms can be found from the weight percentage by respectively dividing it with the molar mass.
Therefore, ratio H:O $= \frac{5.88}{1} : \frac{94.11}{16}$ $= 1 : 1$
Hence, $E m p i r i c a l f o r m u l a = H O$ .

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