Question

An insect crawls a distance of $4m$ along north in $10seconds$ and then a distance of $3m$ along east in $5seconds$. The average velocity of the insect is : (in m/s)

• A. $\frac{1}{3}$
• B. $\frac{1}{4}$
• C. $\frac{1}{7}$
• D. $\frac{1}{9}$

Answer 1

Answer: (A)

$\frac{1}{3}$

Here, total displacement $OB=\sqrt{O{A}^2+A{B}^2}=\sqrt{4^2+3^2}=5$

The average velocity $=$ total displacement/ total time $=5/(10+5)=1/3$