An insect is at the bottom of a hemispherical ditch of radius 1m. It crawls up the ditch but start slipping after it is at height h from the bottom. If the coefficient of friction between the ground and the insect is 0.75, then h is : (g=10ms−2)
A
0.20m
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B
0.45m
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C
0.60m
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D
0.80m
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Solution
The correct option is A0.20m FBD of the insect can be shown as below
From FBD, for balancing, mgsinθ=f=μmgcosθ ⇒tanθ=μ=0.75=34
From the shown geometry we have, h=R−Rcosθ=R−R(45)=R5 ∴h=R5=0.2m[∵radius,R=1m]