Question

An insect moves along the sides of a wall of dimensions 12 m $\times$ 5 m starting from one corner and reaches the diagonally opposite corner. If the insect takes 2 s for its motion, then find the ratio of average speed to the average velocity of insect.

• A. 17 : 13
• B. 12 : 5
• C. 13 : 5
• D. 17 : 12

Answer 1

The correct option is A

17 : 13

Total distance covered by the insect = AB + BC = 17
Total displacement of the insect = AC = 13 (By pythagoras theorem)

$\frac{Averagespeed}{Averagevelocity}=\frac{\left[\frac{Totaldistance}{time}\right]}{\left[\frac{Totaldisplacement}{time}\right]}=\left[\frac{Totaldistance}{Totaldisplacement}\right]=\frac{17}{13}=17:13$.