Question

An insect of negligible mass is sitting on a block of mass. M tied with a spring of force constant k. the block perform simple harmonic motion with amplitude A in front of a plane mirror place as shown the maximum speed of insect relative to it image will be

• A. $A\sqrt{\frac{k}{M}}$
• B. $\frac{A\sqrt{3}}{2}\sqrt{\frac{k}{M}}$
• C. $A\sqrt{3}\sqrt{\frac{k}{M}}$
• D. $2A\sqrt{\frac{M}{A}}$

Answer 1

The correct option is A $A\sqrt{\frac{k}{M}}$

$V_{CB}$ Relahve speed of intersect wrt image

$=V_S-V_{IS}$

In Case of plane mirror velocity $II$ to mirror remains same and one get radius

$V_{max}$ of $m=Aw$

$=A\sqrt{\frac{k}{m}}$

$V_1=V\cos 60$

$=\frac{V}{2}$

$V_S-V_{3S}=2V_{\perp }$

$=2\times A\sqrt{\frac{k}{m}}\times \frac{1}{2}$

$=A\sqrt{\frac{k}{m}}$