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Question

An integrating factor for the differential equation
1+x2)dx(tan1yx)dy=0

[MP PET 1993]


A

tan1y

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B

etan1y

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C

11+y2

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D

1x(1+y2)

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Solution

The correct option is A

tan1y


(1+y2)dx(tan1yx)dy=0dydx=1+y2tan1yxdxdy=tan1y1+y2y1+y2dxdy+x1+y2=tan1y1+y2
This is equation of the form dxdy+px=Q
So, I.F. =e p dy=e11+y2dy=etan1y


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