An integrating factor of the differential equation $(1 + y + x^{2} y) d x + (x + x^{3}) d y = 0$ is

$e^{x}$

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$x^{2}$

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$\frac{1}{x}$

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$x$

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Solution

The correct option is D
$x$

$P = \frac{1}{x} \Rightarrow I . F = x$

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Similar questions

An integrating factor of the differential equation $(1 + y + x^{2} y) d x + (x + x^{3}) d y = 0$ is

(1 + y + x^{2} y) d x + (x + x^{3}) d y = 0

An intergrating factor of the equation $(1 + y + x^{2} y) d x + (x + x^{3}) d y = 0$ is

(1 + y + x^{2} y) d x + (x + x^{3}) d y = 0

(1 + y + x^{2} y) d x = (x + x^{3}) d y

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