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Question

An inverted vessel (bell) lying at the bottom of a lake 50.6 m deep has 50 cc of air trapped in it. The bell is brought to the surface of lake. The volume of the trapped air will now be

A
200 cc
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B
250 cc
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C
300 cc
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D
350 cc
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Solution

The correct option is D 300 cc
Let the Po=105 N/m2,
Assuming process to be isothermal ,P1V1=P2V2
(P0+ρgh)×50=P0V2
(105+1000×10×50.6)×50=105V2
V2=300 cc

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