An ion has 3 unit positive charge, its mass numbers is $27$ and atomic number is 13. How many electrons, neutrons and protons are there in the ion?

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Solution

Mass number= $27 = n_{p} + n_{n}$
Atomic number= $13 = n_{e} = n_{p}$
It has a $+ 3$ charge
$∴ n_{e} = 13 - 3 = 10$ = electrons
$n_{p} = 13$ = protons
$n_{n} = 27 - 13 = 14$ neutrons

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Q. Question 9
The ion of an element has 3 positive charges. Mass number of the atom is 27 and the number of neutrons is 14. What is the number of electrons in the ion?
(a) 13
(b) 10
(c) 14
(d) 16

Q. Question 9
The ion of an element has 3 positive charges. Mass number of the atom is 27 and the number of neutrons is 14. What is the number of electrons in the ion?
(a) 13
(b) 10
(c) 14
(d) 16

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An ion has 3 unit positive charge, its mass numbers is 27 and atomic number is 13. How many electrons, neutrons and protons are there in the ion?

Mass number= 27=np+nnAtomic number= 13=ne=npIt has a +3 charge∴ne=13−3=10= electronsnp=13= protonsnn=27−13=14 neutrons

An ion has 3 unit positive charge, its mass numbers is $27$ and atomic number is 13. How many electrons, neutrons and protons are there in the ion?

Mass number= $27 = n_{p} + n_{n}$
Atomic number= $13 = n_{e} = n_{p}$
It has a $+ 3$ charge
$∴ n_{e} = 13 - 3 = 10$ = electrons
$n_{p} = 13$ = protons
$n_{n} = 27 - 13 = 14$ neutrons