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Thomson's Discovery of Electrons

An ionized H-...

Question

An ionized $H$ -molecule consists of an electron and two protons. The protons are separated by a small distance of the order of angstrom. In the ground state,

the electrons, orbit would go around the protons

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the molecule will soon decay in a proton and a

H

-atom

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the energy would be

(2)^{4}

times that of a

H

-atom

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the electron would not move in circular orbits

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Solution

The correct option is D the electron would not move in circular orbits
In a hydrogen atom, electron revolves around a fixed proton nucleus in circular path. This can be explained by Bohr model. But the case of ionised $H$ -molecule which consists of two protons in nucleus and where protons are separated by a small distance of the order of angstrom, cannot be explained by Bohr model. Hence in this case, the ground state the electron would not move in circular orbits, the electrons orbit will go around the protons instead of moving in their usual circular path around the nucleus.

$Final Answer :$ (a),(c)

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Thomson's Discovery of Electrons

Standard XII Chemistry

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An ionized H-molecule consists of an electron and two protons. The protons are separated by a small distance of the order of angstrom. In the ground state,

An ionized $H$ -molecule consists of an electron and two protons. The protons are separated by a small distance of the order of angstrom. In the ground state,