Question

An iron ball at 104°F is dropped in a mug containing​ water at 40°C. ​ The heat will ______.

• A. flow from the iron ball to the water
• B. flow from the water to the iron ball​
• C. not flow at all
• D. increase for both

Answer 1

The correct option is C not flow at all

We first need to know the temperature on a common scale.

Converting ${40}^{\circ }C$ to Fahrenheit:

$x^{\circ }C=[\frac{9}{5}x+32{]}^{\circ }F$
${40}^{\circ }C=[\frac{9}{5}\times 40+32{]}^{\circ }F$
${40}^{\circ }C=[72+32{]}^{\circ }F$
${40}^{\circ }C={104}^{\circ }F$

Heat flows from a body at high temperature to a body at low temperature. Since the iron ball and the mug of water is at same temperature, no heat will flow at all.​