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Standard XII

Physics

Potentiometer

An iron const...

Question

An iron constant thermocouple is to be used to measure temperature between 0 and 300 $^{o} C$ with reference junction at 0 $^{o} C$ , the emf induced at 100 $^{o} C$ and 300 $^{o} C$ are
$E_{100} = 5268 μ V, E_{300} = 16325 μ V .$
Then the nonlinearity at 100 $^{o} C$ as a percentage of full scale is

-3.23%

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-1.06%

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-0.96%

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+3.23%

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Solution

The correct option is B -1.06%
$E_{100} = 5268 μ V$
$E_{300} = 16325 μ V$

By the linear relationship

$E_{100} must be = \frac{E_{300}}{3}$
$∴ E_{100} = \frac{16325}{3} = 5441.66 μ V$

$% age error$

$= \frac{5268 - 5441.66}{16325} \times 100 = - 1.06 %$

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An iron constant thermocouple is to be used to measure temperature between 0 and 300 oC with reference junction at 0oC, the emf induced at 100 oC and 300oC are E100=5268 μV,E300=16325 μV. Then the nonlinearity at 100oC as a percentage of full scale is

The correct option is B -1.06%E100=5268 μV E300=16325 μV By the linear relationship E100 must be=E3003 ∴E100=163253=5441.66μV % age error =5268−5441.6616325×100=−1.06%

The correct option is B -1.06%
$E_{100} = 5268 μ V$
$E_{300} = 16325 μ V$

By the linear relationship

$E_{100} must be = \frac{E_{300}}{3}$
$∴ E_{100} = \frac{16325}{3} = 5441.66 μ V$

$% age error$

$= \frac{5268 - 5441.66}{16325} \times 100 = - 1.06 %$