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Question

An iron rod of 0.2 cm2 cross-sectional area is subjected to a magnetizing field of 1200 Am1. The susceptibility of iron is 599. The magnetic flux produced is:

A
5.43×105 Wb
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B
0.904×105 Wb
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C
0.904 Wb
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D
1.81×105 Wb
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Solution

The correct option is D 1.81×105 Wb
The permeability is given by
μ=μ0(1+χ)
Putting all values for iron rod

μ=4π×107(1+599)

=7.536×104H/m
The magnetic field produced is

B=μH

=7.536×104H/m×1200Am1

Magnetic flux, ϕ=B.A=BAcosθ
Assuming field is applied perpendicular to the cross sectional area (B||A)

ϕ=BA=7.536×104H/m×

1200Am1×0.2×104m2

=1.81×105Wb

Hence, option (b) is correct.

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