Question

An iron rod of 0.5 cm² area of cross section is subjected to a magnetizing field of 1200 Am^-1. If magnetic susceptibility of iron is 599, calculate (i) µ (ii) B (iii) φ (magnetic flux) produced.

Answer 1

Dear Student,

$$\begin{gathered} \mathrm{\mu }={\mathrm{\mu }}_0\left(1+\mathrm{\chi }\right) \\ \mathrm{\mu }=4\mathrm{\pi }\times {10}^{-7}\times \left(1+599\right) \\ \mathrm{\mu }=7.536\times {10}^{-4}\mathrm{T}\mathrm{m}/\mathrm{A} \\ \mathrm{B}=\mathrm{\mu H} \\ \mathrm{B}=7.536\times {10}^{-4}\times 1200 \\ \mathrm{B}=0.904\mathrm{T} \\ \mathrm{Magnetic}\mathrm{flux},\mathrm{\varphi }=\mathrm{BA} \\ \mathrm{\varphi }=0.904\times 0.5\times {10}^{-4} \\ \mathrm{\varphi }=1.808\times {10}^{-4}\mathrm{Wb} \end{gathered}$$