An iron rod of diameter 1cm and length 8cm is drawn into a wire of length 18m of uniform thickness. Find the thickness of the wire?
0.06 cm
Volume of the rod = πr2h=(π)×(12)2×8=2πcm3
Volume of the wire = πr2h=(π)×(r)2×1800=1800πr2cm3
Volume of the rod (old solid shape) = Volume of the wire (New solid shape)
2 π=1800πr2
r2=1900
r = 130
Diameter = 115=0.06cm