An iron rod of susceptibility 599 is subjected to a magnetising field of 1200Am−1. The permeability of the material of the rod is :(μ0=4π×10−7T mA−1)
A
2.4π×10−5T mA−1
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B
2.4π×10−7T mA−1
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C
2.4π×10−4T mA−1
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D
8×10−5T mA−1
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Solution
The correct option is C2.4π×10−4T mA−1 Given, χm=599, μ0=4π×10−7T mA−1 H=1200A/m
We know that,
Permeability of the material, μ=μ0(1+χm) ⇒μ=4π×10−7(1+599) ∴μ=2.4π×10−4T mA−1