wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

An iron rod of volume 103 m3 an drelative permiability 1000 is placed as core in a solenoid with 10 turns/cm. If a current of 0.5 A is passed through the solenoid, then the magnetic of the rod will be nearly

A
50×102 Am2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5×102 Am2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
500×102 Am2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.5×102 Am2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 5×102 Am2
Given,

Volume of iron, V=103 m3
Relative permeability, μr=1000
Number of turns per unit length, n=10
Magnetic moment of an iron core solenoid,

M=(μr1)×NiA
M=(μr1)×NiVlM=(μr1)×NliV
M=999×10102×0.5×103=499.5500.

flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solenoid Core in Magnetic Field
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon