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Question

An iron rod of volume 103 m3 an drelative permiability 1000 is placed as core in a solenoid with 10 turns/cm. If a current of 0.5 A is passed through the solenoid, then the magnetic of the rod will be nearly

A
50×102 Am2
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B
5×102 Am2
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C
500×102 Am2
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D
0.5×102 Am2
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Solution

The correct option is B 5×102 Am2
Given,

Volume of iron, V=103 m3
Relative permeability, μr=1000
Number of turns per unit length, n=10
Magnetic moment of an iron core solenoid,

M=(μr1)×NiA
M=(μr1)×NiVlM=(μr1)×NliV
M=999×10102×0.5×103=499.5500.

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