An iron tank with an open top is cylindrical in shape. It has a height 10m and radius 7m. It gets corroded at a rate of 3 sq. meter/day. The number of days in which it gets completely corroded is (Take pi= $\frac{22}{7}$ )

192

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202

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198

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208

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Solution

The correct option is C
198

Total surface area of the tank = Curved Surface area + Base area
$= 2 π r h + π r^{2}$
$= 2 \times \frac{22}{7} \times 7 \times 10 + \frac{22}{7} \times 7^{2}$
$= 594 m^{2}$
Total no. of days $= \frac{T o t a l S u r f a c e A r e a o f t a n k}{A r e a c o r r o d e d p e r d a y}$
$= \frac{594}{3} = 198$

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An iron tank with an open top is cylindrical in shape. It has a height 10m and radius 7m. It gets corroded at a rate of 3 sq. meter/day. The number of days in which it gets completely corroded is (Take pi=227)

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