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Question

An iron transformer assumed to be 100 % efficient. The ration of the secondary truns to the primary truns is 1:20. A 240 V ac supply is connected to the primary coil. What is the current in the primary coil?

A
0.1 A
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B
0.14 A
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C
2 A
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D
40 A
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Solution

The correct option is A 0.1 A
As this is 100 % efficient this means the power in the secondary coil will be same as the power in the primary coil
i.e, IpVp=IsVs
Ip=IsVsVp
As we know that the ratio of emf is equal to the ratio of the number of turns.
So, Ip=Is.NsNp=VsRs.NsNp=(NSNP).VpRs.NsNp
Ip=N2sN2pVpRs
Ip=(120)2.2406
Ip=110=0.1 A

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