1
Question
An iron us dropped into a well sound of splash is heard after 4.23 second if the depth of the well is 78.4 m then find the speed of sound in air
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Solution
If
t
1
is the time taken by iron block to reach bottom then
t
1
=
√
2
H
g =
√
2
×
78.4
m
9.8
m
s
−
2 =
4
s
Time taken by sound to reach observer
=
4.23
s
−
4
s
=
0.23
s
Speed of sound
=
Distance
Time =
78.4 m
0.23 s =
340.87 m/s.
If
t
1
is the time taken by iron block to reach bottom then
t
1
=
√
2
H
g
t
1
is the time taken by iron block to reach bottom then
t
1
=
√
2
H
g
=
√
2
×
78.4
m
9.8
m
s
−
2
√
2
×
78.4
m
9.8
m
s
−
2
=
4
s
Time taken by sound to reach observer
=
4.23
s
−
4
s
=
0.23
s
Speed of sound
=
Distance
Time
4
s
Time taken by sound to reach observer
=
4.23
s
−
4
s
=
0.23
s
Speed of sound
=
Distance
Time
=
78.4 m
0.23 s
78.4 m
0.23 s
=
340.87 m/s.
340.87 m/s.
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