Question

An irrational number between 2 and 2.5 is:​

• A. $\sqrt{22}$
• B. $\sqrt{9}$
• C. $\sqrt{11}$
• D. $\sqrt{5}$

Answer 1

The correct option is D $\sqrt{5}$

Given that, we need to get irrational number between 2 and 2.5

On calculating,
$\sqrt{2}2=\mathrm{4.69041...}$
$\sqrt{9}=3$
$\sqrt{1}1=\mathrm{3.31662...}$
$\sqrt{5}=\mathrm{2.23606...}$

Since, $\sqrt{2}2$ and $\sqrt{1}1$ is more than 2.5 and $\sqrt{9}$ is a rationl number.

$\therefore$ An irrational number between 2 and 2.5 is $\sqrt{5}$ (i.e,$\sqrt{2\times 2.5}$) since its approximate value is 2.236.