Question

An irregular piece of metal weighs $10.00g$ in air and $8.00g$ when submerged in water. Find the volume of the metal and its density.

Answer 1

Relative density of metal$=\frac{weightinair}{changeinweightinwater}=\frac{10}{2}=5$

$\therefore$ Density of metal$=5{\rho }_w=5000$ $kg/m^3$

Now, volume$=\frac{mass}{density}$
$=\frac{10\times {10}^{-3}}{5000}=2\times {10}^{-6}{m}^3$