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Difference between Internal Energy and Enthalpy

an isochoric ...

Question

an isochoric reversible process

Δ U = 19.90 k J, Δ H = 24.058 k J; w = 0

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Δ U = - 19.90 k J, Δ H = 24.058 k J; w = 0

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Δ U = 19.90 k J, Δ H = - 24.058 k J; w = 0

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None of these

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Solution

The correct option is A $Δ U = 19.90 k J, Δ H = 24.058 k J; w = 0$
For, isochoric process, V = constant
Hence, $w = 0$
Therefore, $q = Δ U = 19.9 k J$
$Δ H = \int n C_{p} d T = 24.04 k J$

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