An isolated capacitor with a capacitance C has a potential difference between the plates of V, which leaves on each plate a charge $Q$ .
A dielectric is then inserted in-between the plates, what affect does this have on the electric field between the plates?

The electric field increases in magnitude.

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The electric field magnitude is not affected.

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The electric field decreases in magnitude.

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The direction of the electric field changes as well as the magnitude.

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Solution

The correct option is B The electric field decreases in magnitude.
When a dielectric is placed between the charged plates of a capacitors , due to polarisation in dielecric , an electric field is generated inside the dielectric , which is in opposite direction of the electric field between the plates , as a result of this , magnitude of electric field decreases between the plates .

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Similar questions

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Q. Assertion: The electrostatic force between the plates of a charged isolated capacitor decreases when dielectric fills whole space between plates.
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Q. A capacitor of capacitance ‘C’ is connected with a battery of emf ε as shown. After full charging a dielectric of same size of capacitor and dielectric constant k is inserted then choose correct statements. (capacitor is always connected to battery)

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An isolated capacitor with a capacitance C has a potential difference between the plates of V, which leaves on each plate a charge Q.A dielectric is then inserted in-between the plates, what affect does this have on the electric field between the plates?

An isolated capacitor with a capacitance C has a potential difference between the plates of V, which leaves on each plate a charge $Q$ .
A dielectric is then inserted in-between the plates, what affect does this have on the electric field between the plates?