An isolated particle of mass $m$ is moving in a horizontal plane $(x y)$ , along the $x -$ axis, at a certain height above the ground. It suddenly explodes into two fragments of masses $\frac{m}{4}$ and $\frac{3 m}{4}$ . An instant later, the smaller fragment is at $y = + 15$ cm. The larger fragment at this instant is at:

y = - 5

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y = + 20

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y = + 5

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y = - 20

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Solution

The correct option is C $y = - 5$ cm
COM of the system will remain along the x-axis.
$y \times m / 4 + y^{'} \times 3 m / 4 = 0$
thus, $y^{'} = - y / 3 = - 15 / 3 = - 5 c m$

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