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Standard IX

Physics

Alpha Decay

An isolated p...

Question

An isolated particle of mass m is moving in a horizontal x-y plane?along the x-axis at a certain height above the ground. It explodes suddenly into two fragments of masses m/4 and 3 m/4. An instant later, the smaller fragment is at y = + 15 cm. What is the position of larger fragment at this instant?

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Solution

Dear Student ,
as the particle of mass m is moving along x axis its potential as well as kinetic energy about y axis is O.
Hence, by conservation of energy
mgh= (m/4)g15 + (3m/4)gy =0 { because h along y axis is 0}
or , (-mg ) x 15=3 x mgy
hence y= -5cm

Regards

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Dear Student , as the particle of mass m is moving along x axis its potential as well as kinetic energy about y axis is O. Hence, by conservation of energy mgh= (m/4)g15 + (3m/4)gy =0 { because h along y axis is 0} or , (-mg ) x 15=3 x mgy hence y= -5cm Regards

Dear Student ,
as the particle of mass m is moving along x axis its potential as well as kinetic energy about y axis is O.
Hence, by conservation of energy
mgh= (m/4)g15 + (3m/4)gy =0 { because h along y axis is 0}
or , (-mg ) x 15=3 x mgy
hence y= -5cm

Regards