An isolated particle of mass $m$ is moving in a horizontal $x y -$ plane along the x-axis, at a certain height above the ground. It suddenly explodes into two fragments of masses $\frac{m}{4}$ & $\frac{3 m}{4}$ . An instant later, the smaller fragment is at y = +15cm. The larger fragment at this instant is at

Y = - 5 cm

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y = + 20 cm.

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y = + 5 cm

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y = - 20 cm

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Solution

The correct option is A Y = - 5 cm
As the particle of mass m is moving along x axis its potential as well as kinetic energy about y-axis is 0.
now by conservation of energy
mgh= $\frac{m}{4}$ g $\times 15$ + $\frac{3 m}{4}$ g $\times$ y=0
NOTE: h along y axis is 0
$\frac{- 15}{4}$ = $\frac{3}{4}$ y
y=-5cm

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