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Oxidative Hydroboration of Alkynes

An isomer of ...

Question

An isomer of the complex $C o B r C l_{2} (e n)_{2} (H_{2} O)$ , on reaction with concentrated $H_{2} S O_{4}$ (dehydrating agent), suffers no loss in weight and on reaction with $A g N O_{3}$ solution it gives only white precipitate, which is soluble in $N H_{3}$ solution.

The correct formula of the complex is:

[C o B r (H_{2} O) (e n)_{2}] C l_{2}

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[C o C l (e n)_{2} (H_{2} O)] B r C l

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[C o B r C l (e n)_{2}] C l . H_{2} O

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[C o C l_{2} (e n)_{2}] B r . H_{2} O

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Solution

The correct option is A $[C o B r (H_{2} O) (e n)_{2}] C l_{2}$
If there is no loss of weight with concentrated $H_{2} S O_{4}$ then complex does not have water of crystallisation, complex gives white precipitate of $A g C l$ .
Hence, the complex is $[C o B r (H_{2} O) (e n)_{2}] C l_{2}$

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Similar questions

C o B r C l_{2} (e n)_{2} (H_{2} O)

H_{2} S O_{4}

A g N O_{3}

N H_{3}

M .5 N H_{3} . C l . S O_{4}

A

B

A

A g N O_{3}

B

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C o S O_{4} C l .5 N H_{3}

A g N O_{3}

B a C l_{2}

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H N O_{3}

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N H_{4} O H

A g N O_{3}

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