An isosceles right angled triangle has area $8 c m^{2}$ . Find the length of its hypotenuse.

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Solution

Sides of isosceles are Equal , let them be $x$

Area of right Angled isosceles Triangle $= \frac{1}{2} \times x \times x = 8 \Rightarrow x = 4 c m$

Now, the Length of the Hypotenuse is $= \sqrt{4^{2} + 4^{2}} = 4 \sqrt{2} c m$

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If an isosceles right triangle has area $8 c m^{2}$ then the length of its hypotenuse is
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(b) $\sqrt{48} c m$
(c) $\sqrt{24} c m$
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An isoceles right triangle has an area of 8 cm². Find the length of its hypotenuse

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An isosceles right angled triangle has area 8cm2. Find the length of its hypotenuse.

Sides of isosceles are Equal , let them be xArea of right Angled isosceles Triangle =12×x×x=8⇒x=4 cmNow, the Length of the Hypotenuse is =√42+42=4√2 cm

An isosceles right angled triangle has area $8 c m^{2}$ . Find the length of its hypotenuse.

Sides of isosceles are Equal , let them be $x$

Area of right Angled isosceles Triangle $= \frac{1}{2} \times x \times x = 8 \Rightarrow x = 4 c m$

Now, the Length of the Hypotenuse is $= \sqrt{4^{2} + 4^{2}} = 4 \sqrt{2} c m$