Question

An isosceles trapezium has an area of 36 cm², the parallel sides are 12 cm and 6 cm respectively. Find the height of the trapezium.

• A. 28 cm
• B. 32 cm
• C. 24 cm
• D. 20 cm

Answer 1

The correct option is C

24 cm

Let the height be 'h' cm.

$\text{The area of a trapezium is given by:}$
$A=\frac{1}{2}\times \text{(Sum of parallel sides)}\times \text{(height)}$
$\Rightarrow 36=\frac{1}{2}\times (12+6)\times h$

$\Rightarrow 36=\frac{1}{2}\times 18\times h$

$\Rightarrow 36=9\times h$
$\Rightarrow h=4cm$