Question

An isosceles trapezoidal prism has a base area of $234m^2$ and parallel sides of the base measure 12 m and 14 m. Find the altitude of the base of the prism.

Answer 1

$Areaoftheisoscelestrapezoidalbase$

$=\frac{1}{2}\times \left(sumofthelengthsofparallelsides\right)\times altitude$

$\Rightarrow 234=\frac{1}{2}\times (12+14)\times altitude$

$\Rightarrow 234=\frac{1}{2}\times 26\times altitude$

$\Rightarrow 234=13\times altitude$

$\Rightarrow Altitude=\frac{234}{13}$

$\Rightarrow Altitude=18m$