An isosceles triangle has vertices at (4,0), (-4,0), and (0,8) The length of the equal sides is

\sqrt{5}

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4 \sqrt{5}

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3 \sqrt{5}

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Solution

The correct option is B $4 \sqrt{5}$
Length of side = $\sqrt{{(4 - 0)}^{2} + {(0 - 8)}^{2}} = \sqrt{80} = 4 \sqrt{5}$

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