An isosceles triangle is inscribed in a circle such that one of its sides is the diameter of the circle. Find the measure of the side of the triangle(other than diameter) if the radius of the circle is 8 m.

16 m

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8√2m

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8 m

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16√2 m

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8/√2 m

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Solution

The correct option is B
8√2m

The length of the hypotenuse of the triangle is 16 m and the measure of the length of the other side be `x' m.

2x $^{2}$ = 256

$\Rightarrow$ x = 8 $\sqrt{2}$ m

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An isosceles triangle is inscribed in a circle such that one of its sides is the diameter of the circle. Find the measure of the side of the triangle(other than diameter) if the radius of the circle is 8 m.

The correct option is B 8√2m The length of the hypotenuse of the triangle is 16 m and the measure of the length of the other side be `x' m. 2x2 = 256 ⇒x = 8√2 m

The correct option is B
8√2m

The length of the hypotenuse of the triangle is 16 m and the measure of the length of the other side be `x' m.

2x $^{2}$ = 256

$\Rightarrow$ x = 8 $\sqrt{2}$ m