Question

An isosceles triangular plate of base 3 m and altitude 3 m is immersed vertically in an oil of specific gravity 0.8. The base of the plate coincides with the free surface of oil. The centre of pressure will lie at a distance of (from free surface)

• A. 2.5 m
• B. 2 m
• C. 1.5 m
• D. 1 m

Answer 1

The correct option is C 1.5 m


Centre of Pressure depth
$\overline{h}=(\overline{x}+\frac{I_G}{A\overline{x}})=\frac{3}{3}+\left(\frac{3\times 3^3}{36\times \frac{1}{2}\times 3\times 3\times \frac{3}{3}}\right)=1+0.5=1.5m$