An item was bought for $R s 140$ and sold with a profit of $6 %$ . Its $S P$ is $. . . . . . . . . . . . . .$

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Solution

Given,
cost price of the item, $C P$ $=$ $R s 140$
profit per cent, $p r o f i t %$ $=$ $6 %$
selling price of the item, $S P$ $=$ $. . . . . . . . . . . . . .$
Note :
We have the formula to find $S P$ , When $C P$ and $p r o f i t %$ is given ,
i.e. $S P$ $=$ $\frac{C P (100 + p r o f i t %)}{100}$
$S P$ $=$ $\frac{140 (100 + 6)}{100}$
$S P$ $=$ $\frac{140 (106)}{100}$
$S P$ $=$ $\frac{14840}{100}$ ( divide $14840$ by $100$ , we get $148.4$ )
$S P$ $=$ $148.4$ .
Therefore, the answer for given blank is $R s 148.4$ .

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