An item was sold for-540 at a loss of 5 - What was cost price

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Standard VII

Mathematics

Profit % Loss %

An item was s...

Question

An item was sold for $R s . 540$ at a loss of $5 %$ . What was the cost price?

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Solution

S. P of an item $= R s . 540$
Loss $% = 5 %$
Let Cost price be $x$
Therefore, Loss= $C P - S . P = x - S P$ .
Since, loss $% = \frac{Loss}{C . P} \times 100$
$\Rightarrow 5 = \frac{x - S . P}{x} \times 100$
$\Rightarrow 5 = (1 - \frac{S . P}{x}) \times 100$
$\Rightarrow \frac{5}{100} = 1 - \frac{540}{x}$
$\Rightarrow 1 - \frac{1}{20} = \frac{540}{x}$
$\Rightarrow \frac{19}{20} = \frac{540}{x}$
$\Rightarrow x = 540 \times \frac{20}{19}$
$\Rightarrow x = \frac{10800}{19} = 568.42$
Therefore, cost price was $R s . 568.42$

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An item was sold for Rs. 540 at a loss of 5%. What was the cost price?

S. P of an item =Rs. 540 Loss %=5%Let Cost price be x Therefore, Loss=CP−S.P=x−SP.Since, loss%=LossC.P×100⇒5=x−S.Px×100⇒5=(1−S.Px)×100⇒5100=1−540x⇒1−120=540x⇒1920=540x⇒x=540×2019⇒x=1080019=568.42Therefore, cost price was Rs. 568.42

An item was sold for $R s . 540$ at a loss of $5 %$ . What was the cost price?