Question

An L-C-R circuit contains $R=50\Omega$, $L=1mH$ and $C=0.1\mu F$. The impedence of the circuit will be minimum for a frequency of

• A. $\frac{{10}^5}{2\pi }Hz$
• B. $\frac{{10}^6}{2\pi }Hz$
• C. $2\pi \times {10}^{5}Hz$
• D. $2\pi \times {10}^{6}Hz$

Answer 1

The correct option is A $\frac{{10}^5}{2\pi }Hz$

Impedance of L-C-R circuit will be minimum for a resonant frequency so,
$v_0=\frac{1}{2\pi \sqrt{LC}}$
$=\frac{1}{2\pi \sqrt{1\times {10}^{-3}\times 0.1\times {10}^{-6}}}=\frac{{10}^5}{2\pi }Hz$