An LCR circuit contains resistance of 110 - and a supply of 220 V at 300 rad-s angular frequency- If only capacitance is removed from the circuit- current lags behind the voltage by 45- If on the other hand- only inductor is removed the current leads by 45- with the applied voltage- The rms current flowing in the circuit will be-

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Standard XII

Physics

Inductor

An LCR circui...

Question

An LCR circuit contains resistance of $110 Ω$ and a supply of $220 V$ at $300 rad/s$ angular frequency. If only capacitance is removed from the circuit, current lags behind the voltage by $45^{\circ}$ . If on the other hand, only inductor is removed the current leads by $45^{\circ}$ with the applied voltage. The rms current flowing in the circuit will be:

2.5 A

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1 A

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2 A

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1.5 A

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Solution

The correct option is C $2 A$
When L and C are connected with R in series the circuit will come in resonance So, current in the circuit will be:
$I_{r m s} = \frac{V_{r m s}}{R} = \frac{220}{110} = 2 A$

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The correct option is C 2 AWhen L and C are connected with R in series the circuit will come in resonance So, current in the circuit will be: Irms=VrmsR=220110=2 A

The correct option is C $2 A$
When L and C are connected with R in series the circuit will come in resonance So, current in the circuit will be:
$I_{r m s} = \frac{V_{r m s}}{R} = \frac{220}{110} = 2 A$