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Question

An LCR circuit has L=10 mH,R=150 Ω and C=1 μF connected in series to a source of 1502cosωt volt. At a frequency that is 50% of the resonant frequency, calculate the average power (in watt) dissipated per cycle.

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Solution

ω0= resonance frequency.
ω0=1LC=110×103×1×106=1104=104Hz
For, ω=ω02=5×103Hz
Z=R2+(ωL1Cω)2=(150)2+(50200)2=1502
P decipated=Vrms2Rcosϕ=15021502×cosπ4
=150×1501502×12=1502=75W

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