An LCR circuit with $100 Ω$ resistance is connected to an AC source of 200 V and angular frequency of 300 rad/s. When only capacitor is removed, current lags behind the voltage by $60^{\circ}$ . When only inductor is removed, current leads voltage by $60^{\circ}$ , then rms current in LCR circuit is

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Solution

$X_{L} = \sqrt{3} \times 100 Ω, X_{C} = \sqrt{3} \times 100 Ω$
$Z = \sqrt{R^{2} + (X_{L} - X_{C})^{2}} = 100$
$i = \frac{ε}{2} = \frac{200}{100} = 2 A$

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