An $L C R$ series ac circuit is at resonance with $10 V$ each across $L, C$ and $R$ . If the resistance is halved, the respective voltages across $L, C$ and $R$ are

10 V, 10 V

and

5 V

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10 V, 10 V

and 10

V

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20 V, 20 V

and

5 V

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20 V, 20 V

and

10 V

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Solution

The correct option is B $20 V, 20 V$ and $10 V$
Let initial current and resistance be i and R respectively.
Inductive Resistance = $R_{L}$
Capacitive Resistance = $R_{C}$
At resonance, R = $R_{C} = R_{L}$
When resistance is halved current will be doubled.

Thus,

V(resistive) = $2 i \times (R / 2) = i R = 10 V$
V(capacitive) = $2 i \times (R_{C}) = 20 V$
V(Inductive) = $2 i \times (R_{L}) = 20 V$ .

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An LCR series ac circuit is at resonance with 10 V each across L,C and R. If the resistance is halved, the respective voltages across L,C and R are

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