An LCR series circuit is at resonance with 10v each across L, C & R. If the resistance is halved, the respective voltage across L, C & R are

a) 10v, 10v & 5v. b) 10v, 10v & 10v. c) 20v, 20v & 5v

d) 20v, 20v & 10v

MTG finger tips. Chapter ac . Que.no. 63. Answers.d

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Solution

Vl is voltage drop across L
Vc is voltage drop across C
Vr is voltage drop across R
V is voltage of the source
At resonance, entire source voltage will be dropped across resistance because Vl =Vc and their effective value is zero. So voltage of the source
V = 10V =IR

Since this value does not change, and since R is halved, I doubles. So Vr = 10 V itself.

Since L and C are the same, Xl and Xx are the same. But the voltage drop across them are given by IXl and IXc. Since the current has doubled, voltage across them also doubles.
So Vl=Vc =2x10=20 V

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An LCR series circuit is at resonance with 10v each across L, C & R. If the resistance is halved, the respective voltage across L, C & R are a) 10v, 10v & 5v. b) 10v, 10v & 10v. c) 20v, 20v & 5v d) 20v, 20v & 10v MTG finger tips. Chapter ac . Que.no. 63. Answers.d

An LCR series circuit is at resonance with 10v each across L, C & R. If the resistance is halved, the respective voltage across L, C & R are

a) 10v, 10v & 5v. b) 10v, 10v & 10v. c) 20v, 20v & 5v

d) 20v, 20v & 10v

MTG finger tips. Chapter ac . Que.no. 63. Answers.d