Question

An $LVDT$ is used in an accelerometer to measure seismic-mass displacement. The LVDT and signal conditioning output is $0.31\left(\frac{mV}{mm}\right)$ with $a\pm 2cm$ maximum core displacement. The spring constant is $240\left(N/m\right)$ and the core mass is $0.05kg$. The maximum acceleration $\left(inm/se{c}^2\right)$ that can be measured is

• A. 96

Answer 1

The correct option is A 96
$\text{we know the relation}$

$ma=k\Delta x$

$Acceleration\left(a\right)=\frac{k\Delta x}{m}$

$=\frac{240\times 2\times {10}^{-2}}{0.05}$

$a=96\left(m/se{c}^2\right)$