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Impedance Triangle

An LVDT signa...

Question

An LVDT signal conditioning circuit is shown below. the LVDT is operated at 5V, 1 kHz rated supply. For the fixed input displacement the ratio $f_{o} / f_{D}$ is ?
Where,
$V_{1}, f_{1} = LVDT output voltage and frequency$
$V_{D}, f_{D} = PSD output voltage and frequency$
$V_{f}, f_{f} = Filter output voltage and frequency$
$V_{o}, f_{o} = Amplifier output voltage and frequency$

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Solution

The correct option is A 1
Filter and amplifier do not change the frequency of the phase sensitive detector output. They are simply used to remove the ripple and amplify the DC voltage respectively. Hence the required ratio is :

$\frac{f_{o}}{f_{D}} = 1$

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