An n-p- n transistor circuit has -0-985 - If I C -2 mA- then value of I b isA- 0-003 mAB- 0-66 mAC- 0-015 mAD- 0-03 mA

The correct option is D 0.03 mA α =I_c/I_e =I_c/I_c+I_b=0.985 I_c=0.985(I_c+I_b) I_c=0.985 I_c+0.985 I_b 0.985 I_b=0.015 I_c=0.015× 2 mA I_b=0.015× 2/0.985=0. ...

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Byju's Answer

Standard XII

Physics

Potentiometer

An n-p- n tra...

Question

An n – p – n transistor circuit has $α = 0.985$ . If $I_{c} = 2 m A$ , then value of $I_{b}$ is____.

0.03 mA

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0.003 mA

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0.66 mA

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0.015 mA

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Solution

The correct option is A
0.03 mA

$α = \frac{I_{c}}{I_{e}} = \frac{I_{c}}{I_{c} + I_{b}} = 0.985$

$I_{c} = 0.985 (I_{c} + I_{b})$

$I_{c} = 0.985 I_{c} + 0.985 I_{b}$

$0.985 I_{b} = 0.015 I_{c} = 0.015 \times 2 m A$

$I_{b} = \frac{0.015 \times 2}{0.985} = 0.03 m A$

$I_{b} \approx 0.03 m A$

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An n – p – n transistor circuit has α=0.985. If Ic=2mA, then value of Ib is____.

The correct option is A 0.03 mA α=IcIe=IcIc+Ib=0.985 Ic=0.985(Ic+Ib) Ic=0.985 Ic+0.985 Ib 0.985 Ib=0.015 Ic=0.015×2 mA Ib=0.015×20.985=0.03mA Ib≈0.03 mA

An n – p – n transistor circuit has $α = 0.985$ . If $I_{c} = 2 m A$ , then value of $I_{b}$ is____.

The correct option is A
0.03 mA

$α = \frac{I_{c}}{I_{e}} = \frac{I_{c}}{I_{c} + I_{b}} = 0.985$

$I_{c} = 0.985 (I_{c} + I_{b})$

$I_{c} = 0.985 I_{c} + 0.985 I_{b}$

$0.985 I_{b} = 0.015 I_{c} = 0.015 \times 2 m A$

$I_{b} = \frac{0.015 \times 2}{0.985} = 0.03 m A$

$I_{b} \approx 0.03 m A$