An n-type silicon bar 0-1 cm long and 100 - m2 in cross-sectional area has a majority carrier concentration of 5 - 1020 -m3 and the carrier mobility is 0-13 m2- V-s at 300 K- If the charge of an electron is 1-6 - 10-19 Coulomb- then the resistance of the bar is

Ans :(a) Given that, l = 0.1 cm = 10^ 3 m A= 100 μ m^2 = 100 × 10^ 12 m^2 n= 5 × 10^20 /m^3 μ _n = 0.13 m^2 /V sec q= 1.6 × 10^ 19 Col We know that nbsp; Con ...

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An n-type sil...

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An n-type silicon bar $0.1 c m$ long and $100 μ m^{2}$ in cross-sectional area has a majority carrier concentration of $5 \times 10^{20} / m^{3}$ and the carrier mobility is $0.13 m^{2} / V - s$ at $300 K$ . If the charge of an electron is $1.6 \times 10^{- 19}$ Coulomb, then the resistance of the bar is

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Solution

Ans :(a)
Given that,
$l = 0.1 c m = 10^{- 3} m$
$A = 100 μ m^{2} = 100 \times 10^{- 12} m^{2}$
$n = 5 \times 10^{20} / m^{3}$
$μ_{n} = 0.13 m^{2} / V - s e c$
$q = 1.6 \times 10^{- 19} C o l$
We know that
Conductivity $= σ = n q μ_{n}$
Resistivity = $ρ = \frac{1}{σ}$
Resistance $= \frac{ρ l}{A} = \frac{l}{σ A}$
$R = \frac{10^{- 3}}{(5 \times 10^{20}) \times (1.6 \times 10^{- 19}) (0.13) (100 \times 10^{- 12})}$
$R = 10^{6} Ω$

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An n-type silicon bar 0.1 cm long and 100 μm2 in cross-sectional area has a majority carrier concentration of 5×1020/m3 and the carrier mobility is 0.13 m2/V−s at 300 K. If the charge of an electron is 1.6×10−19 Coulomb, then the resistance of the bar is

Ans :(a) Given that, l=0.1 cm=10−3m A=100 μm2=100×10−12m2 n=5×1020/m3 μn=0.13m2/V−sec q=1.6×10−19Col We know that Conductivity =σ=nqμn Resistivity = ρ=1σ Resistance =ρlA=lσA R=10−3(5×1020)×(1.6×10−19)(0.13)(100×10−12) R=106Ω