An NMOS transistor operates in saturation region with an overdrive voltage of 0-25 V is required to have a - m equal to that of an npn transistor operated at IC-0-1 mA- Then the value of ID must be equal to Assume- Vr-26 mV

For NMOS device, The transconductance is equal to, δ_m=∂ I_P∂ V_GS=∂∂ V_GS[12μ_nC_oxWL(V_GS V_TH)^2] δ_m1=μ_nC_oxWL(V_0 ) or δ_m1=2I_D(V_0)=2I_D0.25=8I_ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Inductor

An NMOS trans...

Question

An NMOS transistor operates in saturation region with an overdrive voltage of 0.25 V is required to have a $δ_{m}$ equal to that of an npn transistor operated at $I_{C} = 0.1 m A .$ Then the value of $I_{D}$ must be equal to (Assume, $V_{r} = 26 m V$ )

0.48 m A

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.25 m A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.36 m A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 m A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A

$0.48 m A$
For NMOS device,

The transconductance is equal to,

$δ_{m} = \frac{\partial I_{P}}{\partial V_{G S}} = \frac{\partial}{\partial V_{G S}} [\frac{1}{2} μ_{n} C_{o x} \frac{W}{L} (V_{G S} - V_{T H})^{2}] δ_{m 1} = μ_{n} C_{o} x \frac{W}{L} (V_{0}) o r δ_{m 1} = \frac{2 I_{D}}{(V_{0})} = \frac{2 I_{D}}{0.25} = 8 I_{D}$

transconductance in non BJT,

$δ_{m 2} = \frac{I_{C}}{V_{T}} g i v e n δ_{m 1} = δ_{m 2} 8 I_{D} = \frac{I_{C}}{V_{T}} \Rightarrow I_{D} = \frac{0.1 \times 10^{- 3}}{8 \times 26 \times 10^{- 3}} ∴ I_{D} = 0.48 m A$

Suggest Corrections

Similar questions

Q. In the circuit shown below, the transistor operates at

I_{D} = 0.4 m A

and

V_{D} = 0.5 V .

The NMOS transistor has

V_{t} = 0.7 V, μ_{n} C_{\propto} = 100 μ A / V^{2}, L = 1 μ m

and

ω = 32 μ m .

Assume

λ = 0.

The value of

R_{s} i s

Q. An npn transistor receives _________ voltage to the collector terminal and _________ voltage to the base terminal for proper operation

Q. Consider the circuit shown in the figure below:

The transistors

Q_{1}

and

Q_{2}

are identical and operated in active mode such that

I_{C} 1 = 10 I_{C 2}

and

V_{T} = 26

mV. If the value of voltage

V_{1} = 25

mV, then the value of

V_{2}

is equal to ___mV.

The transfer characteristics of a base biased transistor has the operation regions namely, cut off, active region and saturation region. For using the transistor as an amplifier it has to operate in the region:

Q. Consider the transistor circuit shown in the figure below .

Assume the transistor is biased in saturation region with

g_{m} = 5 m A / V .

Then the value of input resistance

R_{i n}

is equal to

Join BYJU'S Learning Program

An NMOS transistor operates in saturation region with an overdrive voltage of 0.25 V is required to have a δm equal to that of an npn transistor operated at IC=0.1 mA. Then the value of ID must be equal to (Assume, Vr=26 mV)

The correct option is A 0.48 mAFor NMOS device, The transconductance is equal to, δm=∂IP∂VGS=∂∂VGS[12μnCoxWL(VGS−VTH)2] δm1=μnCoxWL(V0)or δm1=2ID(V0)=2ID0.25=8ID transconductance in non BJT, δm2=ICVTgiven δm1=δm28ID=ICVT⇒ ID=0.1×10−38×26×10−3∴ID=0.48mA

An NMOS transistor operates in saturation region with an overdrive voltage of 0.25 V is required to have a $δ_{m}$ equal to that of an npn transistor operated at $I_{C} = 0.1 m A .$ Then the value of $I_{D}$ must be equal to (Assume, $V_{r} = 26 m V$ )