An O16 nucleus is spherical and has a radius R and a volume V=43πR3. According to the empirical observations, the volume of the 54X128 nucleus assumed to be spherical is V′ and radius is R′. Then
A
V′=8V
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B
V′=2V
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C
R′=2R
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D
R′=8R
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Solution
The correct options are AV′=8V CR′=2R R=RoA1/3 A= mass no RR′=161281/3 R′=2R Volume∝R3 Hence, V′=8V