Question

An object $10cm$ in height is placed at a distance of $36cm$ from a concave mirror. If the image is formed at a distance of $18cm$ in front of the mirror, find the height of image.

Answer 1

Height of object $\left(h_1\right)=10cm$

Object distance $\left(\mu \right)=-36cm$

Image distance $\left(\vartheta \right)=-18cm$

$m=-\frac{\vartheta }{\mu }=\frac{h_2}{h_1}$

$\frac{-(-18)}{-36}=\frac{h_2}{10}$

$h_2=-5cm$

Height of image = 5 cm