An object $15 c m$ high is placed $10 c m$ from the optical center of a thin lens. Its image is formed $25 c m$ from the optical center on the same side of the lens as the object. The height of the image is:

2.5 c m

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0.2 c m

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16.7 c m

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37.5 c m

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Solution

The correct option is C $37.5 c m$
height of image is $m a g n i f i c a t i o n \times h e i g h t_{o b j e c t} = \frac{v}{u} \times 15 = 15 \times \frac{25}{10} = 37.5$
option $D$ is correct

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An object 15cm high is placed 10cm from the optical center of a thin lens. Its image is formed 25cm from the optical center on the same side of the lens as the object. The height of the image is:

The correct option is C 37.5cmheight of image is magnification×heightobject=vu×15=15×2510=37.5option D is correct

An object $15 c m$ high is placed $10 c m$ from the optical center of a thin lens. Its image is formed $25 c m$ from the optical center on the same side of the lens as the object. The height of the image is:

The correct option is C $37.5 c m$
height of image is $m a g n i f i c a t i o n \times h e i g h t_{o b j e c t} = \frac{v}{u} \times 15 = 15 \times \frac{25}{10} = 37.5$
option $D$ is correct